Why do you have a 2nd arg in your lambda called undefined?
Also, you will want to check for the existence of console.log before you
call it, otherwise you will get a runtime error if firebug is switched off.
On 4 Jul 2011 20:30, Sam3k <srolda...@gmail.com> wrote:
Why does the following script works within the application code but it
doesn't when I type it in the firebug console. It throws the following
error:
TypeError: debug.log is not a function
My goal with this script is to make an object from where I can log
things to the console, store javascript speed performance in different
areas, and turn off if no cookie is set.
file: Debugger.js
(function (window, undefined) {
function Debugger() {
this.test = 'xxxxxx';
}
Debugger.prototype.log = function(data) {
console.log(data);
}
var _debug = new Debugger();
window.debug = _debug;
debug.log('DEFE"DEFEF'); // this works
})(window);
debug.log('OUTSIDE DKEGFYG'); // this works too
Also any constructive feedback is greatly appreciate it.
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