Hi: Shirley
You just have logic errors in your code. Add j--; (or j=j-1;) in the middle of
two for statements. You will be okay.
Which company do you work?
Shirley Chen wrote:
> Thanks for replying. But my boss insists that I use array because vector
> costs more memory and time.
>
> >From: Shawn Zhu <[EMAIL PROTECTED]>
> >Reply-To: A mailing list about Java Server Pages specification and
> > reference <[EMAIL PROTECTED]>
> >To: [EMAIL PROTECTED]
> >Subject: Re: arrays
> >Date: Wed, 20 Dec 2000 13:06:06 -0800
> >
> >Why don't you just use Vector?
> >--------
> >Vector v_queryResult = New Vector();
> >...
> >if(tmpString.indexOf('C')!=-1)
> >{
> > v_queryResult.addElement((Object)tmpString);
> >}
> >--------
> >Then there's no need for Array2.
> >
> >
> > > -----Original Message-----
> > > From: Shirley Chen [mailto:[EMAIL PROTECTED]]
> > > Sent: Wednesday, December 20, 2000 11:39 AM
> > > To: [EMAIL PROTECTED]
> > > Subject: arrays
> > >
> > >
> > > Hi,
> > >
> > > I have a question, somebody please help me:
> > >
> > > I have a vector which will keep all the names the user typed
> > > in. Then the
> > > user supposes can do a query like "give me all the name which
> > > starts with
> > > 'C'". In order to do that, I do something like this:
> > >
> > > ...
> > > String[] array1 = new String[myVector.size()];
> > > String tempString = "";
> > > int j=0;
> > >
> > > for (int i=0; i<myVector.size(); i++)
> > > {
> > > tmpString = (String)myVector.get(i);
> > > if (tmpString.indexOf('C') != -1)
> > > {
> > > array1[j] = tmpString;
> > > j++;
> > > }
> > > }
> > >
> > > //since array1 may not be filled up with data, I transfer it
> > > to another
> > > String array so I know how many element in the array
> > >
> > > String array2 = new String[j];
> > > for (int i=0; i<j; i++)
> > > {
> > > array2[i] = array1[i];
> > > }
> > >
> > > // then I will do display. Supposedly, say, array2.length is
> > > 20, if the user
> > > wants to display first 5, I will display only the first 5
> > > records, if the
> > > user wants to display 30, and I will display 20 instead.
> > > ...
> > >
> > > I can display all the situations ok except when myVector
> > > contains the names
> > > that all start with "C" (which means array2.length should be
> > > myVector.size()). then the program will crash. I think it
> > > might be array
> > > out of bound problem, but I don't know how to fix it. Please help me.
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