Here’s one way:

A = {
 (4000,0.97613,1.6e6),
 (2000,0.97613,800000.0),
 (8000,0.97613,3.2e6),
 (1000,0.97613,400000.0)
}

Float64[row[3] for row in A]

 — John

On Mar 11, 2014, at 9:34 PM, Matthew Crews <matthewcr...@gmail.com> wrote:

>  (4000,0.97613,1.6e6) 
>  (2000,0.97613,800000.0)
>  (8000,0.97613,3.2e6) 
>  (1000,0.97613,400000.0)

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