Here’s one way:

A = {
(4000,0.97613,1.6e6),
(2000,0.97613,800000.0),
(8000,0.97613,3.2e6),
(1000,0.97613,400000.0)
}

Float64[row[3] for row in A]

— John

On Mar 11, 2014, at 9:34 PM, Matthew Crews <matthewcr...@gmail.com> wrote:

> (4000,0.97613,1.6e6) 
> (2000,0.97613,800000.0)
> (8000,0.97613,3.2e6) 
> (1000,0.97613,400000.0)

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