Here’s one way: A = { (4000,0.97613,1.6e6), (2000,0.97613,800000.0), (8000,0.97613,3.2e6), (1000,0.97613,400000.0) }
Float64[row[3] for row in A] — John On Mar 11, 2014, at 9:34 PM, Matthew Crews <matthewcr...@gmail.com> wrote: > (4000,0.97613,1.6e6) > (2000,0.97613,800000.0) > (8000,0.97613,3.2e6) > (1000,0.97613,400000.0)