Thanks all, those look like neat solutions.
------------------------------------------
Carlos
On Fri, May 16, 2014 at 11:36 PM, Stefan Karpinski <ste...@karpinski.org>wrote:
> When you write fill!(arr, ChannVals()) you are asking to fill arr with
> the one value that is the result of evaluating ChannVals() once. Doing
> anything else would be bizarre. We could have a version of fill! that takes
> a thunk so you could write
>
> fill!(arr) do
> ChannVals()
> end
>
>
> That would have the desired effect as well, but it seems to me that using
> a comprehension is just as easy in that case.
>
>
> On Fri, May 16, 2014 at 4:21 PM, Ivar Nesje <iva...@gmail.com> wrote:
>
>> @Jameson They are immutable, but they contain references to mutable
>> arrays, and all the immutable types will reference the same arrays. That
>> way you would not just need a copy but a deepcopy. That will probably be
>> too much overhead for fill!(), and will be problematic if someone decided
>> to fill! an array with some large structure.
>>
>> On the other hand, I think it would be reasonable for fill! to take a
>> shallow copy of mutable types. Not sure what others think on that subject
>> though.
>>
>> Ivar
>>
>> kl. 17:01:56 UTC+2 fredag 16. mai 2014 skrev Jameson følgende:
>>>
>>> Since they are immutable, fill! did exactly what you wanted
>>>
>>> On Friday, May 16, 2014, Tim Holy <tim....@gmail.com> wrote:
>>>
>>>> Try
>>>>
>>>> arr = [ChannVals() for i = 1:10]
>>>>
>>>> On Friday, May 16, 2014 01:27:18 AM Carlos Becker wrote:
>>>> > Hello all,
>>>> >
>>>> > I wanted to create an array of an immutable type and initialize an
>>>> empty
>>>> > copy in each (with the default constructor).
>>>> > I am wondering which is the best way to do it, so far:
>>>> >
>>>> > immutable ChannVals
>>>> > taus::Vector{Float64}
>>>> > alphas::Vector{Float64}
>>>> >
>>>> > ChannVals() = new( Float64[], Float64[] )
>>>> > end
>>>> >
>>>> > # create 10 new instances
>>>> > arr = ChannVals[ChannVals() for i=1:10]
>>>> >
>>>> >
>>>> > Now, a neat but incorrect way is to do
>>>> >
>>>> > arr = Array( ChannVals, 10 )
>>>> > fill!(allVals, ChannVals())
>>>> >
>>>> > because it will fill them with the same instance.
>>>> > Is there a neat way, such as a fillwithcopies!() ?
>>>> >
>>>> >
>>>> > Cheers.
>>>>
>>>
>
