This pseudocode almost works. Just replace Int64[1:len(outputarray)] with 1:length(outputarray).
There’s also a bug in your core logic, but I’ll leave fixing that as an exercise to the reader. — John On Jul 30, 2014, at 1:03 PM, yaoismyh...@gmail.com wrote: > Hi guys, > > I asked this in a previous thread, but because that diverged off-topic from > my existing question, I decided to create a new thread. > > Anyhow, say I have an array > > outputarray = > Float64[-1.23423,-3.23423,-2.34234,-2.12342,1.23234,2.23423,-2.23432,5.2341,0.01111,1.23423] > > This array lists the output of some function. I want to count the number of > times that the function passes by or equals 0 while emerging from a negative > f(x). > > In pseudocode, I want to do: > > function counter(outputarray) > count = 0 > for i in Int64[1:len(outputarray)] > if outputarray[i] >= 0 && outputarray[i-1] < 0 > count += 1 > end > end > return count > end > > What would be the most efficient way of doing this in Julia? > > Thanks, > Wally
