You need to give default values for each keyword argument:
type Foo
bar
baz
Foo(;bar=10, baz=1) = new(bar, baz)
end
On Sunday, November 2, 2014 1:05:37 PM UTC-5, Kevin Owens wrote:
>
> I'm using Julia 0.3 something.
>
> If I make a composite type with many fields I may forget the order, but
> remember their names. I'd like to use a constructor where I can use name
> the arguments.
>
> Say I have the composite type
>
> type Foo
>
> bar
>
> baz
>
> end
>
>
> How can I make a constructor that lets me do this
>
> myfoo = Foo(baz=1, bar=2)
>
> I expected this would work
>
>
> type Foo
>
> bar
>
> baz
>
>
> Foo(;bar, baz) = new(bar, baz)
>
> end
>
>
> But when I run it I get
>
> ErrorException("syntax: invalid keyword argument bar")
>
>
> I also tried
>
>
>
> julia> function Foo(;bar, baz)
>
>
> Foo(bar, baz)
>
>
> end
>
>
>
>
> ErrorException("syntax: invalid keyword argument bar")
>
>
>
>
