Is there any way to do it without setting default values? Or, is there a
type you can give to default values so that if you try to use them it will
throw an error? I'm thinking like with R and the "NA" value.
Do keyword arguments have to have default values? It's not clear in the 0.3
documentation on functions that it's the case.
On Sunday, November 2, 2014 12:47:26 PM UTC-6, Jack Minardi wrote:
>
> You need to give default values for each keyword argument:
>
> type Foo
> bar
> baz
> Foo(;bar=10, baz=1) = new(bar, baz)
> end
>
>
> On Sunday, November 2, 2014 1:05:37 PM UTC-5, Kevin Owens wrote:
>>
>> I'm using Julia 0.3 something.
>>
>> If I make a composite type with many fields I may forget the order, but
>> remember their names. I'd like to use a constructor where I can use name
>> the arguments.
>>
>> Say I have the composite type
>>
>> type Foo
>>
>> bar
>>
>> baz
>>
>> end
>>
>>
>> How can I make a constructor that lets me do this
>>
>> myfoo = Foo(baz=1, bar=2)
>>
>> I expected this would work
>>
>>
>> type Foo
>>
>> bar
>>
>> baz
>>
>>
>> Foo(;bar, baz) = new(bar, baz)
>>
>> end
>>
>>
>> But when I run it I get
>>
>> ErrorException("syntax: invalid keyword argument bar")
>>
>>
>> I also tried
>>
>>
>>
>> julia> function Foo(;bar, baz)
>>
>>
>> Foo(bar, baz)
>>
>>
>> end
>>
>>
>>
>>
>> ErrorException("syntax: invalid keyword argument bar")
>>
>>
>>
>>
