When i do : using Benchmarks @benchmark sin(2.0) I have an error like : ERROR: @benchmark not defined
Has anyone been able to successfully use Benchmarks.jl ? On Wednesday, 3 February 2016 22:58:09 UTC+1, Stefan Karpinski wrote: > > You may want to check out Benchmarks.jl > <https://github.com/johnmyleswhite/Benchmarks.jl>, which goes to > significant lengths to do benchmarking correctly. > > On Wed, Feb 3, 2016 at 4:05 PM, Milan Bouchet-Valat <nali...@club.fr > <javascript:>> wrote: > >> Le mercredi 03 février 2016 à 12:55 -0800, Christopher Alexander a >> écrit : >> > Try doing something like: >> > >> > tic() >> > # my code >> > toc() >> Be careful with tic() and toc() in Julia. In most cases, when >> benchmarking, you should wrap your code in a function to make sure it >> gets specialized on the argument types, instead of running it from the >> REPL. So in general it's better to do: >> @time myfun(arg1, arg2, ...) >> >> See http://docs.julialang.org/en/latest/manual/performance-tips/#measur >> e-performance-with-time-and-pay-attention-to-memory-allocation >> <http://docs.julialang.org/en/latest/manual/performance-tips/#measure-performance-with-time-and-pay-attention-to-memory-allocation> >> >> >> Regards >> >> > On Wednesday, February 3, 2016 at 3:28:28 PM UTC-5, Lytu wrote: >> > > Hello Julia users, >> > > >> > > Can someone tell me what's the equivalent of matlab elapsed cputime >> > > in Julia >> > > >> > > For example i Matlab, we can do this: >> > > t = cputime; >> > > x=4; >> > > iter = 1; >> > > z = ones(1,4); >> > > y=x*2*z; >> > > e = cputime-t >> > > >> > > But in Julia i don't seem to find how to do this. I thought i can >> > > use >> > > t=time() >> > > x=4; >> > > iter = 1; >> > > z = ones(1,4); >> > > y=x*2*z; >> > > e=time()-t >> > > >> > > But time() in Julia is not the elapsed CPU time, it's a wall clock >> > > time. >> > > >> > > Can someone help me? >> > > >> > > Thank you >> > > >> > >
