Diky
On Mon, 16 Apr 2007 11:36:59 +0200, lukas <[EMAIL PROTECTED]> wrote:
Ted jsem cetl, ze to chcete porad nahoru, tak potom pouzijte
BigDecimal.ROUND_UP pripadne BigDecimal.ROUND_CEILING (jine chovani pro
zaporna cisla).
On Mon, 16 Apr 2007 11:33:23 +0200, lukas wrote
a) nemejte menu ulozenou jako double, nejlepe jako BigDecimal
b) s tim pak provest nasledujici:
a = a.multiply(new
BigDecimal(2)).setScale(0,BigDecimal.ROUND_HALF_EVEN).divide(new
BigDecimal(2));
Lukas
On Mon, 16 Apr 2007 11:06:38 +0200, Jan Medek wrote
> a = ( (a % 0.5) != 0 ) ? (Math.floor(a) + 0.5) : (a);
>
> Ale nic moc. :-)
>
> Petr Burdik napsal(a):
> > Ahojte,
> > lamu se ted s funci zaokrouhlovani na 50ti halere nahoru. Neresili
jste
> > to prosim nekdo? Vim ze to hranici s cucanim, ale nejak se mi nedari
> > najit pekny algoritmus.
> >
> > Pekny den
> > Pet
> >
> > --Using Opera's revolutionary e-mail client:
http://www.opera.com/mail/
> >
> >
> >
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