On Fri, Jun 6, 2008 at 11:23 AM, Chris Louden <[EMAIL PROTECTED]> wrote: >> Sometimes the mask is like 255.255.240.0 > > 167.190.0.1 - 167.190.15.254
Okay. 240 decimal is 1111 0000 binary. In this case I have 12 binary digits available for identifying the host. So the IP range of such a subnet is 167.190.0.1 # whose last two octets are "00000000 00000001" to 167.190.15.254 # whose last two octets are "00001111 11111110" Hey, that makes sense. The subnet ID I have is actually 167.190.96.0, with that mask of 255.255.240.0. The 240 means all but the last 12 digits are masked, and the second to last octet is... Anyway, I get it. I'm gonna have to actually convert these to binary to understand the ranges, and the calculators will help me to do that. I get it! I found this PDF helpful, too: http://www.3com.com/other/pdfs/infra/corpinfo/en_US/501302.pdf -- Todd Walton, HelpDesk -- [email protected] http://www.kernel-panic.org/cgi-bin/mailman/listinfo/kplug-list
