I don't know about a fuel flow chart, but the math to calculate it is pretty simple. The 2180 is 75 hp takeoff power at 3600RPM. 2180cc=.077cu ft. 3600RPM=1800 intakes/min for 138.6 cu ft/min or 8316 cu ft/hr. 8316x.08 lbs/cu ft air=665.28 lbs air/hr. Correction for normally aspirated volumetric efficiency 665.28x.95=632 lb/hr. 632lbs air+60 lbs gasoline/hr = 100% power at 10.5:1 F/A ratio. 60lbs/6 lbs/gal = 10.0gph. Best power ratio would be 12:1. You want your fuel system to deliver enough fuel in any scenario on takeoff (SL@10.5:1 standard day) with 150% safety margin to avoid starving the engine under worst case scenario (winter day with very low DA)
For that motor you'd want to run a fuel flow system test and verify it can deliver at least 15gph. For comparison, my electric pump fed system (Facet 3psi cube pumps) delivers a verified 19gph through the system. I hope this is helpful. Adam Deem N8095K KR2 Corvair 3.0L On Sun, Jan 14, 2024 at 2:04 PM Michael R. Humberd via KRnet < krnet@list.krnet.org> wrote: > I am preparing for my aircraft certification and one of the items on the > DAR checklist is a fuel flow test for take off fuel consumption. I have a > Great Plains VW 2180 engine. No luck finding anything online. Does anyone > have a fuel flow chart/ graph showing consumption rate for takeoff? Ref. > 8130.2J 15-4 b (5) > Mike Humberd > N75MH > Sent from my iPad > -- > KRnet mailing list > KRnet@list.krnet.org > https://list.krnet.org/mailman/listinfo/krnet >
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