Avi Kivity wrote: > Agree, but should try a "quit" monitor command first. Signals are racy, > like anything that deals with pids (qemu dies, another process is > fork()ed with the same pid, libvirt kills it).
There is no race in that specific case because qemu is started by libvirtd. libvirtd can savely kill qemu as long as it hasn't collected the exit status via waitpid(). While the qemu zombie hangs around the pid will not be reused. cheers, Gerd ------------------------------------------------------------------------- This SF.net email is sponsored by: Microsoft Defy all challenges. Microsoft(R) Visual Studio 2008. http://clk.atdmt.com/MRT/go/vse0120000070mrt/direct/01/ _______________________________________________ kvm-devel mailing list kvm-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/kvm-devel
