Dear Henry, I am talking about the lead. It doesn't matter what you have in the scattering region if you have a lead where the Fermi energy lies in the gap, the physics should be the same if you consider just a finite part from the lead, with a length typically, of the order of penetration length (few times this characteristic length if you want more precision.) This is valid for any lead, not just a superconducting one. The reason is that in all cases, in the deleted part, the wave function is exponentially small.
I hope this helps. Adel On Sun, Mar 21, 2021 at 8:05 PM Henry Axt <[email protected]> wrote: > Dear Adel, > > I am indeed looking at the case where the Fermi energy is in the gap of > the superconductor. Do you mean to say that the simulation with the > superconductor in the scattering region is that same as a simulation with a > superconductor as a lead and the scattering region's length increased by > the penetration length? > > I'm not quite I understand why there would be a difference at these > energies. At least not in the nature I see them, where if you consider the > case where the superconductor is in the scattering and you increase the > superconducting region's length, yet the differences between these two > simulations don't change. > > Regards, > Henry > -- Abbout Adel
