Hi,
In the meantime, I found another solution for this, but this doesn't appear
to be the easiest way to do it! I used systemStartDelimiterHierarchy instead
which doesn't add any space within a family group. Again, with the LilyPond
exemple, this will give:
[...]
I would be interested if someone find another way to do this... But at
least, this seems to work!
I daresay this might be the best and even the semantically "correct"
solution. Note that the brace connecting Violin 1 and Violin 2 does not
yield an "instrument" that is used to being held together by a brace
(like a piano), but is a mere notational convention. What we really want
is, I think, 4-5 staves of strings with equal rights, the first two of
which happen to be connected by an additional brace.
But I think your usage of systemStartDelimiterHierarchy is not yet
optimal. It can be simplified to
\set StaffGroup.systemStartDelimiterHierarchy = #'((SystemStartBrace a b))
Also, I would not do this via \set, but in a \with block. If you then
also put this into a variable, it gets very easy to use:
\version "2.19.80"
firstTwoBraced = \with {
systemStartDelimiterHierarchy = #'((SystemStartBrace a a))
}
\new StaffGroup \with \firstTwoBraced <<
\new Staff = "Staff_violinI" \with { instrumentName = #"Violin I" } { a }
\new Staff = "Staff_violinII" \with { instrumentName = #"Violin II" }
{ a }
\new Staff = "Staff_viola" \with { instrumentName = #"Viola" } { a }
\new Staff = "Staff_cello" \with { instrumentName = #"Cello" } { a }
\new Staff = "Staff_bass" \with { instrumentName = #"Double Bass" } { a }
>>
With a little bit of scheme, it should even be easy to make this into a
function accepting to parameters, indicating that k staves starting with
the n'th staff should be braced.
Best
Lukas
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