Re: Scheme expressions on lilypond command line (-e)

[Jean Abou Samra]

Le 19/10/2020 à 23:14, Dave Seidel a écrit :

Hi all,

I am trying to define a variable on the command line that I can use within the .ly file. I've tried both

    -e "(define-public part 1)"

and

    -e "(define part 1)"


In the .ly file, I have a Scheme expression

    #(if (= part 0)
      (define partName "")
      (define partName (string-append "S" part))
    )


In either case, I get the error

    GUILE signaled an error for the expression beginning here
    #
     (if (= part 0)
    Unbound variable: part

I guess I'm either defining the variable incorrectly, or dereferencing it incorrectly within the script. Can someone help?

Thanks,
Dave

Hi,

Have a look at

lilypond.org/doc/v2.21/Documentation/usage/command_002dline-usage#basic-command-line-options-for-lilypond.html

You need

#(use-modules (guile-user))

at the top of your LilyPond source.

You can ignore the warning that shows up 
(https://gitlab.com/lilypond/lilypond/-/issues/3613).

Best,
Jean