Here's a possibly good way to do it (I say possibly, because I didn't test it, but it feels like it ought to work). If you're using 8.5 or later, you could do this:
c1 = rgb(100,100,100) c2 = rgb(123,100,100) v1 = vector(c1.red,c1.green,c1.blue) v2 = vector(c2.red,c2.green,c2.blue) put v1.distanceto(v2) -- 23.0000
You would count colors as being the same if their distance from the comparison color is less than a certain amount.
Nice. This seems to make the most conceptual sense, since the rgb color model is described in terms of 3d space. Performance might be a problem, though.
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