Kerry wrote:
>Ok, for a lazy Friday afternoon, here's some code I'm working on
>optimizing (D8):
...
If I understand this correctly, then you need to know, if you have an
odd number and the even number one higher?
on CheckCards a1, a2
return 2*(a1 mod 2)=a2-a1+1
end
(What you do to please gerbils ;-)
Jakob
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