I can't believe I never noticed this after all these years (unless I did
and forgot it a long time ago - a good possibility), but Lingo has no
trunc() function.
Integer rounds up, so integer(2.58) returns 3. There's nothing to slice it.
The age-old workaround to get around this is to add .5 to the source
number, and subtract one from the result, as in:
truncX =(integer(x + .5)) - 1
So I can use that. But what I was looking for and realized doesn't exist
is a trunc function, such that:
truncX =trunc(x)
would return 2 whether x was 2.001 or 2.999.
Sounds like an oversight! :) Or does someone remember something I don't?
(Note that in some languages integer() works like a trunc(), and round()
works like Lingo's integer(). But all we have is integer() and nothing else).
- Tab
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