Well, then maybe I should point out that the two IP addresses are indeed
different, in the third octet:
192.168.140.60 HIPERLF0
192.168.141.60 HIPERLF1
If the intent was to actually assign the same IP to both interfaces,
then they either typoed it, or typoed it in sending it to the mailing
list.
Mark Post
-----Original Message-----
From: Linux on 390 Port [mailto:[EMAIL PROTECTED] On Behalf Of
Alan Altmark
Sent: Monday, November 28, 2005 6:02 PM
To: LINUX-390@VM.MARIST.EDU
Subject: Re: Linux network problem/question
-snip-
With the subsequent post from Steve saying that he can't ping .63 from
.60, either, I would venture that PRIROUTE is not sufficient to fix this
problem. Unfortunately the archive renders the original post
unreadable, but as I can piece together, the given configuration was:
HOME
10.140.1.22 ETH0
10.140.1.24 ETH2
192.168.140.60 HIPERLF0
192.168.141.60 HIPERLF1
; Network First Hop Interface MTU Mask
Subnet
192.168.140 = HIPERLF0 8192 0
192.168.141.60 = HIPERLF1 8192 HOST
10.140.1.24 = ETH2 1500 HOST
10 = ETH0 1500 0.255.255.0
0.140.1.0
; Default for everything else
DEFAULTNET 10.140.1.254 ETH0 1500 0
Assigning the same IP address on different interfaces is a Really Bad
Idea. If dynamic routing is introduced, it will not produce the desired
results. As given, this configuration will send requests for .63
through HIPERLF0, not LF1. If LF1 is the desired interface, then the
192.168.141.60 value in the second entry must change to 192.168.141.63.
The .63 host must have a default
In general, I'm not happy with the two HOST entries. It is a nefarious
attempt to split the respective subnets into two LAN segments. That is
a recipe for failure. In fact, note the subnet mask on the Linux guest:
255.255.255.0. Linux will assume that all 192.168.141 hosts are local
on the hsi1 interface, a valid assumption, but not true based on the VM
configuration.
Alan Altmark
z/VM Development
IBM Endicott
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