On Tue, 20 Jan 2015 20:10:56 -0500, Chris Mason wrote:
> On Tue, Jan 20, 2015 at 8:09 PM, Qu Wenruo <quwen...@cn.fujitsu.com> wrote:
>>
>> -------- Original Message --------
>> Subject: Re: [PATCH] btrfs: Don't call btrfs_start_transaction() on frozen fs
>> to avoid deadlock.
>> From: Chris Mason <c...@fb.com>
>> To: Qu Wenruo <quwen...@cn.fujitsu.com>
>> Date: 2015年01月21日 09:05
>>>
>>>
>>> On Tue, Jan 20, 2015 at 7:58 PM, Qu Wenruo <quwen...@cn.fujitsu.com> wrote:
>>>>
>>>> -------- Original Message --------
>>>> Subject: Re: [PATCH] btrfs: Don't call btrfs_start_transaction() on frozen
>>>> fs to avoid deadlock.
>>>> From: David Sterba <dste...@suse.cz>
>>>> To: Qu Wenruo <quwen...@cn.fujitsu.com>
>>>> Date: 2015年01月21日 01:13
>>>>> On Mon, Jan 19, 2015 at 03:42:41PM +0800, Qu Wenruo wrote:
>>>>>> --- a/fs/btrfs/super.c
>>>>>> +++ b/fs/btrfs/super.c
>>>>>> @@ -1000,6 +1000,14 @@ int btrfs_sync_fs(struct super_block *sb, int 
>>>>>> wait)
>>>>>>                */
>>>>>>               if (fs_info->pending_changes == 0)
>>>>>>                   return 0;
>>>>>> +            /*
>>>>>> +             * Test if the fs is frozen, or start_trasaction
>>>>>> +             * will deadlock on itself.
>>>>>> +             */
>>>>>> +            if (__sb_start_write(sb, SB_FREEZE_FS, false))
>>>>>> +                __sb_end_write(sb, SB_FREEZE_FS);
>>>>>> +            else
>>>>>> +                return 0;
>>>
>>> But what if someone freezes the FS after __sb_end_write() and before
>>> btrfs_start_transaction()?   I don't see what keeps new freezers from 
>>> coming in.
>>>
>>> -chris
>> Either VFS::freeze_super() and VFS::syncfs() will hold the s_umount mutex, so
>> freeze will not happen
>> during sync.
> 
> You're right.  I was worried about the sync ioctl, but the mutex won't be held
> there to deadlock against.  We'll be fine.

There is another problem which is introduced by pending change. That is we will
start and commmit a transaction by changing pending mount option after we set
the fs to be R/O.

I think it is better that we don't start a new transaction for pending changes
which are set after the transaction is committed, just make them be handled by
the next transaction, the reason is:
- Make the behavior of the fs be consistent(both freezed fs and unfreezed fs)
- Data on the disk is right and integrated


Thanks
Miao
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