Nicolas Pitre <nicolas.pi...@linaro.org> writes:

> On Thu, 19 Nov 2015, Måns Rullgård wrote:
>
>> Nicolas Pitre <nicolas.pi...@linaro.org> writes:
>> 
>> > +static inline uint64_t __arch_xprod_64(uint64_t m, uint64_t n, bool bias)
>> > +{
>> > +  unsigned long long res;
>> > +  unsigned int tmp = 0;
>> > +
>> > +  if (!bias) {
>> > +          asm (   "umull  %Q0, %R0, %Q1, %Q2\n\t"
>> > +                  "mov    %Q0, #0"
>> > +                  : "=&r" (res)
>> > +                  : "r" (m), "r" (n)
>> > +                  : "cc");
>> > +  } else if (!(m & ((1ULL << 63) | (1ULL << 31)))) {
>> > +          res = m;
>> > +          asm (   "umlal  %Q0, %R0, %Q1, %Q2\n\t"
>> > +                  "mov    %Q0, #0"
>> > +                  : "+&r" (res)
>> > +                  : "r" (m), "r" (n)
>> > +                  : "cc");
>> > +  } else {
>> > +          asm (   "umull  %Q0, %R0, %Q2, %Q3\n\t"
>> > +                  "cmn    %Q0, %Q2\n\t"
>> > +                  "adcs   %R0, %R0, %R2\n\t"
>> > +                  "adc    %Q0, %1, #0"
>> > +                  : "=&r" (res), "+&r" (tmp)
>> > +                  : "r" (m), "r" (n)
>> 
>> Why is tmp using a +r constraint here?  The register is not written, so
>> using an input-only operand could/should result in better code.  That is
>> also what the old code did.
>
> No, it is worse. gcc allocates two registers because, somehow, it 
> doesn't think that the first one still holds zero after the first usage.  
> This way usage of only one temporary register is forced throughout, 
> producing better code.

Makes sense.  Thanks for explaining.

-- 
Måns Rullgård
m...@mansr.com
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