On Fri, Aug 12, 2016 at 7:28 AM, Josh Poimboeuf <jpoim...@redhat.com> wrote: > On x86_32, when an interrupt happens from kernel space, SS and SP aren't > pushed and the existing stack is used. So pt_regs is effectively two > words shorter, and the previous stack pointer is normally the memory > after the shortened pt_regs, aka '®s->sp'. > > But in the rare case where the interrupt hits right after the stack > pointer has been changed to point to an empty stack, like for example > when call_on_stack() is used, the address immediately after the > shortened pt_regs is no longer on the stack. In that case, instead of > '®s->sp', the previous stack pointer should be retrieved from the > beginning of the current stack page. > > kernel_stack_pointer() wants to do that, but it forgets to dereference > the pointer. So instead of returning a pointer to the previous stack, > it returns a pointer to the beginning of the current stack. > > Fixes: 0788aa6a23cb ("x86: Prepare removal of previous_esp from i386 > thread_info structure") > Signed-off-by: Josh Poimboeuf <jpoim...@redhat.com>
This seems like a valid fix, but I'm not sure I agree with the intent of the code. ®s->sp really is the previous stack pointer in the sense that the stack pointer was ®s->sp when the entry happened. >From an unwinder's perspective, how is: movl [whatever], $esp <-- interrupt any different from: movl [whatever], $esp pushl [something] <-- interrupt Also, does x86_32 do this type of stack switching at all? AFAICS 32-bit kernels don't use IRQ stacks in the first place. Do they? Am I just missing the code that does it? --Andy