Hi, On 12/12/16 15:05, Bartosz Golaszewski wrote:
> +&lcdc {
> + status = "okay";
> + pinctrl-names = "default";
> + pinctrl-0 = <&lcd_pins>;
> +
> + ports {
> + #address-cells = <1>;
> + #size-cells = <0>;
> +
> + lcdc_out: port@1 {
> + #address-cells = <1>;
> + #size-cells = <0>;
> + reg = <1>;
> +
> + lcdc_out_vga: endpoint {
> + reg = <0>;
> + remote-endpoint = <&vga_bridge_in>;
> + };
> + };
> + };
> +};
>
This is not correct. LCDC has just one output, so port@1 doesn't make
sense. It's port@0. But with just one port, you can leave "ports" away.
And you don't need the port's label for anything, if I'm not mistaken. So:
&lcdc {
status = "okay";
pinctrl-names = "default";
pinctrl-0 = <&lcd_pins>;
port {
lcdc_out_vga: endpoint {
remote-endpoint = <&vga_bridge_in>;
};
};
};
Tomi
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