On Mon, Sep 02, 2019 at 03:20:30PM +0300, Andy Shevchenko wrote: > On Mon, Sep 02, 2019 at 03:43:13PM +0800, Tanwar, Rahul wrote: > > On 28/8/2019 11:09 PM, Andy Shevchenko wrote: > > > On Wed, Aug 28, 2019 at 03:00:17PM +0800, Rahul Tanwar wrote:
> > > Does val == 0 follows the table, i.e. makes div == 1? > > > > 0 val means output clock is ref clock i.e. div ==1. Agree that adding > > .val = 0, .div =1 entry will make it more clear & complete. > > > > > > + { .val = 0, .div = 1 }, > > > > + { .val = 1, .div = 2 }, > > > > + { .val = 2, .div = 3 }, > > 1 > > > > > + { .val = 3, .div = 4 }, > > > > + { .val = 4, .div = 5 }, > > > > + { .val = 5, .div = 6 }, > > 1 > > > > > + { .val = 6, .div = 8 }, > > > > + { .val = 7, .div = 10 }, > > > > + { .val = 8, .div = 12 }, > > 2 > > > > > + { .val = 9, .div = 16 }, > > > > + { .val = 10, .div = 20 }, > > > > + { .val = 11, .div = 24 }, > > 4 > > > > > + { .val = 12, .div = 32 }, > > > > + { .val = 13, .div = 40 }, > > > > + { .val = 14, .div = 48 }, > > 8 > > > > > + { .val = 15, .div = 64 }, > > 16 > > > So, now we see the pattern: > > div = val < 3 ? (val + 1) : (1 << ((val - 3) / 3)); It's not complete, but I think you got the idea. > So, can we eliminate table? -- With Best Regards, Andy Shevchenko