This patch will remove old kernels from system selective way.
Signed-off-by: Bhaskar Chowdhury <unixbhas...@gmail.com>
---
scripts/prune-kernel | 16 ++++++++--------
1 file changed, 8 insertions(+), 8 deletions(-)
diff --git a/scripts/prune-kernel b/scripts/prune-kernel
index 74143f229f84..28fae6c91218 100755
--- a/scripts/prune-kernel
+++ b/scripts/prune-kernel
@@ -33,7 +33,7 @@ printf "\t\n Enlist the installed kernels \n\n\n"
cd $boot_dir && pwd
#Bash experts not recomend to run ls inside script,but you can by running that
too
-# ls -1 vmlinuz-*
+# ls -1 vmlinuz-*
#This is the recommended way , little complex but that's what people want to
see!
@@ -42,10 +42,10 @@ find $boot_dir -name "vmlinuz-*" -type f -print0 -exec ls
-1 {} \;
printf "\n\n\n Well, we need to purge some kernel to gain some space.\n\n\n"
-printf "Please give the kernel version to remove: %s"
+printf "Please give the kernel version to remove: %s"
read kernel_version
-remove_old_kernel
+remove_old_kernel
printf "\n\n Remove associated modules too ... \n\n"
@@ -54,7 +54,7 @@ cd $modules_dir && pwd
printf "\n\n\n Enlist the installed modules \n\n\n"
#This is (-1) minus one not l(el)
-# ls -1
+# ls -1
find $modules_dir -name "$kernel_version-*" -type f -print0 -exec ls -1 {} \;
@@ -66,14 +66,14 @@ rm -rf $modules_version
printf "\n\n Done \n\n"
printf "\n\n Want to remove another?[Yn] : %s"
-read response
+read response
if [[ $response == "Y" ]]; then
- printf "Please give another version to remove : %s"
+ printf "Please give another version to remove : %s"
read kernel_version
-remove_old_kernel
+remove_old_kernel
elif [[ $response == "n" ]]; then
@@ -81,4 +81,4 @@ elif [[ $response == "n" ]]; then
fi
-exit 0
+exit 0
--
2.21.0
