On 18/08/2020 13.16, Peter Ujfalusi wrote:
...
>> +static void dma_issue_pending(struct dma_chan *chan)
>> +{
>> + struct ldma_chan *c = to_ldma_chan(chan);
>> + struct ldma_dev *d = to_ldma_dev(c->vchan.chan.device);
>> + unsigned long flags;
>> +
>> + if (d->ver == DMA_VER22) {
>> + spin_lock_irqsave(&c->vchan.lock, flags);
>> + if (vchan_issue_pending(&c->vchan)) {
>> + struct virt_dma_desc *vdesc;
>> +
>> + /* Get the next descriptor */
>> + vdesc = vchan_next_desc(&c->vchan);
>> + if (!vdesc) {
>> + c->ds = NULL;
>> + return;
>> + }
>> + list_del(&vdesc->node);
>> + c->ds = to_lgm_dma_desc(vdesc);
>
> you have set c->ds in dma_prep_slave_sg and the only way I can see that
> you will not leak memory is that the client must terminate_sync() after
> each transfer so that the synchronize callback is invoked between each
> prep_sg/issue_pending/competion.
>
>> + spin_unlock_irqrestore(&c->vchan.lock, flags);
>> + ldma_chan_desc_hw_cfg(c, c->ds->desc_phys,
>> c->ds->desc_cnt);
>> + ldma_chan_irq_en(c);
>> + }
>
> If there is nothing pending, you will leave the spinlock wide open...
you leave it locked...
>
>> + }
>> + ldma_chan_on(c);
>> +}
- Péter
Texas Instruments Finland Oy, Porkkalankatu 22, 00180 Helsinki.
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