Hi Daniel,
On Fri, 21 Aug 2020, Daniel W. S. Almeida wrote:
From: "Daniel W. S. Almeida" <dwlsalme...@gmail.com>
Digital TV devices consist of several independent hardware components
which are controlled by different drivers.
Each media device is controlled by a group of cooperating drivers with the
bridge driver as the main driver.
This patch adds a bridge driver for the Virtual Digital TV driver [vidtv].
This is now commit f90cf6079bf67988 ("media: vidtv: add a bridge
driver") in the media tree.
nore...@ellerman.id.au reported the following error for an m68k
allmodconfig build:
ERROR: modpost: "__udivdi3"
[drivers/media/test-drivers/vidtv/dvb-vidtv-bridge.ko] undefined!
Presumably this fails on other 32-bit platforms, too.
--- /dev/null
+++ b/drivers/media/test-drivers/vidtv/vidtv_mux.c
+static u32 vidtv_mux_check_mux_rate(struct vidtv_mux *m)
+{
+ /*
+ * attempt to maintain a constant mux rate, padding with null packets
+ * if needed
+ */
+
+ u32 nbytes = 0; /* the number of bytes written by this function */
+
+ u64 nbytes_expected; /* the number of bytes we should have written */
+ u64 nbytes_streamed; /* the number of bytes we actually wrote */
+ u32 num_null_pkts; /* number of null packets to bridge the gap */
+
+ u64 elapsed_time_msecs = jiffies_to_usecs(m->timing.current_jiffies -
+ m->timing.past_jiffies);
+
+ elapsed_time_msecs = min(elapsed_time_msecs, (u64)VIDTV_MAX_SLEEP_USECS
/ 1000);
+ nbytes_expected = div64_u64(m->mux_rate_kbytes_sec * 1000,
MSEC_PER_SEC);
Seriously?!?
You multiply by 1000 first, followed by a division by 1000 using an
expensive 64-by-64 division?
+ nbytes_expected *= elapsed_time_msecs;
+
+ nbytes_streamed = m->mux_buf_offset;
+
+ if (nbytes_streamed < nbytes_expected) {
+ /* can't write half a packet: roundup to a 188 multiple */
+ nbytes_expected = roundup(nbytes_expected - nbytes_streamed,
TS_PACKET_LEN);
drivers/media/test-drivers/vidtv/vidtv_mux.o: In function `vidtv_mux_tick':
vidtv_mux.c:(.text+0x788): undefined reference to `__udivdi3'
This is a 64-by-32 division, hence it should use a helper from
<linux/math64.h>.
However, I'm wondering if "nbytes_expected - nbytes_streamed" is
guaranteed to be a "small" number, hence a 32-by-32 division would be
sufficient?
+ num_null_pkts = nbytes_expected / TS_PACKET_LEN;
Likewise.
+ nbytes += vidtv_mux_pad_with_nulls(m, num_null_pkts);
+ }
+
+ return nbytes;
+}
--- /dev/null
+++ b/drivers/media/test-drivers/vidtv/vidtv_s302m.c
+static void vidtv_s302m_compute_pts(struct vidtv_encoder *e)
+{
+ u64 count = e->sample_count;
+ struct vidtv_access_unit *au = e->access_units;
+
+ while (au) {
+ count += au->num_samples;
+
+ au->pts = count *
+ CLOCK_UNIT_90KHZ / e->sampling_rate_hz;
drivers/media/test-drivers/vidtv/vidtv_s302m.o: In function
`vidtv_s302m_encode':
vidtv_s302m.c:(.text+0x2ac): undefined reference to `__udivdi3'
Likewise.
+
+ au = au->next;
+ }
+}
Gr{oetje,eeting}s,
Geert
--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- ge...@linux-m68k.org
In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
-- Linus Torvalds
