> -----Original Message-----
> From: Doug Anderson <diand...@chromium.org>
> Sent: Tuesday, October 27, 2020 4:21 AM
> To: Rakesh Pillai <pill...@codeaurora.org>
> Cc: Abhishek Kumar <kua...@chromium.org>; Kalle Valo
> <kv...@codeaurora.org>; ath10k <ath...@lists.infradead.org>; LKML
> <linux-kernel@vger.kernel.org>; linux-wireless <linux-
> wirel...@vger.kernel.org>; Brian Norris <briannor...@chromium.org>
> Subject: Re: [PATCH] ath10k: add option for chip-id based BDF selection
> 
> Hi,
> 
> On Sat, Oct 24, 2020 at 9:40 AM Rakesh Pillai <pill...@codeaurora.org> wrote:
> >
> > >         if (bd_ie_type == ATH10K_BD_IE_BOARD) {
> > > +               /* With variant and chip id */
> > >                 ret = ath10k_core_create_board_name(ar, boardname,
> > > -                                                   sizeof(boardname), 
> > > true);
> > > +                                               sizeof(boardname), true, 
> > > true);
> >
> > Instead of adding a lot of code to generate a second fallback name, its
> better to just modify the condition inside the function
> “ath10k_core_create_board_name” to allow the generation of BDF tag using
> chip id, even “if ar->id.bdf_ext[0] == '\0 “.
> >
> > This will make sure that the variant string is NULL, and just board-id and
> chip-id is used. This will help avoid most of the code changes.
> > The code would look as shown below
> >
> > @@ -1493,7 +1493,7 @@ static int ath10k_core_create_board_name(struct
> ath10k *ar, char *name,
> >         }
> >
> >         if (ar->id.qmi_ids_valid) {
> > -               if (with_variant && ar->id.bdf_ext[0] != '\0')
> > +               if (with_variant)
> 
> Wouldn't the above just be "if (with_chip_id)" instead?  ...but yeah,
> that would be a cleaner way to do this.  Abhishek: do you want to post
> a v2?


The parameter name passed to this function is "with_variant", since other 
non-qmi targets (eg QCA6174) use this as a flag to just add the variant field.
This can be renamed to something meaningful for both qmi and non-qmi targets.

> 
> -Doug

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