On 01/05/2013 02:07 PM, Alex Shi wrote:
> There is 4 situations in the function:
> 1, no task allowed group;
> so min_load = ULONG_MAX, this_load = 0, idlest = NULL
> 2, only local group task allowed;
> so min_load = ULONG_MAX, this_load assigned, idlest = NULL
> 3, only non-local task group allowed;
> so min_load assigned, this_load = 0, idlest != NULL
> 4, local group + another group are task allowed.
> so min_load assigned, this_load assigned, idlest != NULL
>
> Current logical will return NULL in first 3 kinds of scenarios.
> And still return NULL, if idlest group is heavier then the
> local group in the 4th situation.
>
> Actually, I thought groups in situation 2,3 are also eligible to host
> the task. And in 4th situation, agree to bias toward local group.
> So, has this patch.
>
> Signed-off-by: Alex Shi <alex....@intel.com>
> ---
> kernel/sched/fair.c | 12 +++++++++---
> 1 file changed, 9 insertions(+), 3 deletions(-)
>
> diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
> index 6d3a95d..3c7b09a 100644
> --- a/kernel/sched/fair.c
> +++ b/kernel/sched/fair.c
> @@ -3181,6 +3181,7 @@ find_idlest_group(struct sched_domain *sd, struct
> task_struct *p,
> int this_cpu, int load_idx)
> {
> struct sched_group *idlest = NULL, *group = sd->groups;
> + struct sched_group *this_group = NULL;
> unsigned long min_load = ULONG_MAX, this_load = 0;
> int imbalance = 100 + (sd->imbalance_pct-100)/2;
>
> @@ -3215,14 +3216,19 @@ find_idlest_group(struct sched_domain *sd, struct
> task_struct *p,
>
> if (local_group) {
> this_load = avg_load;
> - } else if (avg_load < min_load) {
> + this_group = group;
> + }
> + if (avg_load < min_load) {
> min_load = avg_load;
> idlest = group;
> }
> } while (group = group->next, group != sd->groups);
>
> - if (!idlest || 100*this_load < imbalance*min_load)
> - return NULL;
> + if (this_group && idlest != this_group)
> + /* Bias toward our group again */
> + if (100*this_load < imbalance*min_load)
> + idlest = this_group;
> +
> return idlest;
> }
>
Reviewed-by:Preeti U Murthy
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