commit e38d457de7be63e6ced1ea254aa51466deb1fef0
pinctrl: pinmux: Release all taken pins in pinmux_enable_setting
Introduced a bug in the release pin mechanism.
All the pins (taken or not) where released.
For instance, if a i2c function has already taken pins 5 and 6.
And the pins of function PHY are requested (pins 3 4 5 6 7).
The pins 3 and 4 will be taken, pin 5 is already taken, so the function
fails.
And we have pins 3 and 4 release, which is ok. But also pins 5 and 6 !.
And also pin 7 (which will have its mux_usecount to -1...)
This patch reset the original behaviour.
Signed-off-by: Richard Genoud <richard.gen...@gmail.com>
---
drivers/pinctrl/pinmux.c | 2 ++
1 files changed, 2 insertions(+), 0 deletions(-)
diff --git a/drivers/pinctrl/pinmux.c b/drivers/pinctrl/pinmux.c
index 1a00658..917e830 100644
--- a/drivers/pinctrl/pinmux.c
+++ b/drivers/pinctrl/pinmux.c
@@ -409,6 +409,8 @@ int pinmux_enable_setting(struct pinctrl_setting const
*setting)
dev_err(pctldev->dev,
"could not request pin %d on device %s\n",
pins[i], pinctrl_dev_get_name(pctldev));
+ /* On error release *only* taken pins */
+ num_pins = i - 1; /* this pin just failed */
goto err_pin_request;
}
}
--
1.7.2.5
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