On 03/19/2013 10:50 AM, Mark Brown wrote:
> On Mon, Mar 18, 2013 at 05:41:49PM -0600, Stephen Warren wrote:
>
>> It took a very quick look at the patch and couldn't see anything
>> actively wrong. I wonder if one of the existing unconverted users
>> of .parse_val() relies on the in-place modification of the buffer
>> as well as getting the result back, and so should have been
>> converted to calling both .parse_inplace() and then
>> .parse_val()?
>
> Possibly, though you'd have thought that if it were just that one
> of the other users would have noticed - my primary development
> board uses regmap extensively for example. Does seem the most
> likely option though. Can't test anything again until Friday
> sadly.
>
> Might also be some unusual code path WM8903 exercises, though again
> it's pretty simple.
I haven't thought through why the patch in question causes/exposes the
issue yet, but I have found out what the problem is.
_regmap_bus_raw_write() formats the value into work_buf + reg_bytes +
pad_bytes, i.e. work_buf + 1.
For the first regmap_write() that the WM8903 driver does, work_buf is
now xx 89 03.
_regmap_raw_write() then memcpy()s from val (i.e. work_buf + 1) to
workbuf, and parses the value to send to the caching code:
> if (!map->cache_bypass && map->format.parse_val) { unsigned int
> ival; int val_bytes = map->format.val_bytes; for (i = 0; i <
> val_len / val_bytes; i++) { memcpy(map->work_buf, val + (i *
> val_bytes), val_bytes); ival =
> map->format.parse_val(map->work_buf);
This corrupts that value at work_buf + 1 since it overlaps the copy
destination at work_buf. work_buf is now 89 03 03.
_regmap_raw_write() then formats the register address into work_buf,
yielding 00 03 03.
That data stream is then sent over I2C, causing a write to register 0
(correct) of value 03 03 (rather than 89 03).
If I comment out the memcpy, and instead pass the value address
directly to .parse_val(), everything works again.
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