>>   #ifdef CONFIG_RANDOM32_SELFTEST
>>   static void __init prandom_state_selftest(void);
>> +#else
>> +#define prandom_state_selftest() (void)0

> Fine by me. I think you can remove this '(void)0' here, though.

That's the standard way to write a no-op statement in C.

I seem to recall there's a reason that the empty string can cause problems
in some syntactic contexts, but I can't figure out what the situation is.

At first, I thought of the obvious:

if (condition)
        prandom_state_selftest();
unconditional_code();

... but the semicolon makes that work.  I'll try to remember
the reason.

(I know that nobody uses it in any such context, but it's
good manners to make a function-like macro behave as exactly
like a function as possible.)
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