On 01/11, [email protected] wrote:
>
> @@ -382,6 +382,7 @@ static inline void drop_init_fpu(struct task_struct *tsk)
> else
> fxrstor_checking(&init_xstate_buf->i387);
> }
> + clear_thread_flag(TIF_LOAD_FPU);
OK, in this case tsk should be current. Still I think clear_tsk_thread_flag()
will look more consistent.
> @@ -435,24 +436,32 @@ static inline void switch_fpu_prepare(struct
> task_struct *old, struct task_struc
> prefetch(new->thread.fpu.state);
I am wondering if these prefetch()es in switch_fpu_prepare() make
sense after this patch.
> + } else
> + /*
> + * The new task does not want an FPU state restore,
> + * and may not even have an FPU state. However, the
> + * old task may have left TIF_LOAD_FPU set.
> + * Clear it to avoid trouble.
> + *
> + * CR0.TS is still set from a previous FPU switch
> + */
> + clear_thread_flag(TIF_LOAD_FPU);
I got lost ;) Simply can't understand what this change tries to do.
And it looks "obviously wrong"... OK, suppose that a TIF_LOAD_FPU task
schedules before it returns to user mode (and calls switch_fpu_finish).
Why should we clear its flag if the new task doesn't want FPU ?
"CR0.TS is still set" is not true if use_eager_fpu()... OTOH, .TS can
be also set even if preload == T above, when we set TIF_LOAD_FPU.
> -static inline void switch_fpu_finish(struct task_struct *new)
> +static inline void switch_fpu_finish(void)
> {
> - if (test_and_clear_thread_flag(TIF_LOAD_FPU)) {
> - __thread_fpu_begin(new);
> - if (unlikely(restore_fpu_checking(new)))
> - drop_init_fpu(new);
> - }
> + struct task_struct *tsk = current;
> +
> + __thread_fpu_begin(tsk);
> +
> + if (unlikely(restore_fpu_checking(tsk)))
> + drop_init_fpu(tsk);
> }
Again, I am totally confused. After this patch the usage of set_thread_flag()
in switch_fpu_prepare() becomes wrong (see my reply to 2/11), but it is quite
possible I misunderstood these patches.
Oleg.
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