* Li, Aubrey <aubrey...@linux.intel.com> wrote:

> >>  - in x86_reduced_hw_init() set 'legacy_pic' to 'null_legacy_pic'
> >>
> >>  - clean up 'global_clock_event' handling: instead of a global 
> >>    variable, move its management into x86_platform_ops::get_clockevent()
> >>    and set the method to hpet/pit/abp/etc. specific handlers that
> >>    return the right clockevent device.
> >>
> >>  - in your x86_reduced_hw_init() function add the hpet clockevent
> >>    device to x86_platform_ops::get_clockevent, overriding the default
> >>    PIT.
> 
> how about this one?
> 
> diff --git a/arch/x86/kernel/acpi/boot.c b/arch/x86/kernel/acpi/boot.c
> index b9e30da..70955d6 100644
> --- a/arch/x86/kernel/acpi/boot.c
> +++ b/arch/x86/kernel/acpi/boot.c
> @@ -1541,6 +1541,16 @@ int __init early_acpi_boot_init(void)
>        */
>       early_acpi_process_madt();
> 
> +     /*
> +      * Override x86_init functions and bypass legacy pic
> +      * in hardware-reduced ACPI mode
> +      */
> +     if (acpi_gbl_reduced_hardware) {
> +             x86_init.timers.timer_init = x86_init_noop;
> +             x86_init.irqs.pre_vector_init = x86_init_noop;
> +             legacy_pic = &null_legacy_pic;
> +     }

Sounds good to me, assuming it builds, boots and works! :-)

A couple of extra suggestions:

1)

I'd suggest moving it into its own dedicated, appropriately named 
static function, to make it clear that 'ACPI Reduced Hardware' init 
happens there.

2)

I'd also initialize it like this:

                x86_init.timers.timer_init      = x86_init_noop;
                x86_init.irqs.pre_vector_init   = x86_init_noop;
                legacy_pic                      = &null_legacy_pic;

to make the noop patterns stand out better.

3)

Once all is said and done, please also make acpi_gbl_reduced_hardware 
a flag internal to the ACPI code, not exposed to and used by other 
bits of x86 code.

> If the above makes sense, I'll send poweroff and reboot change 
> together in a seperate patch.

Yeah, please send them in a single series though, so they form a 
logical group.

Thanks,

        Ingo
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