This function is only called for stopped child tasks, so the
fpu__save() branch will never get called - remove it.

Reviewed-by: Borislav Petkov <[email protected]>
Cc: Andy Lutomirski <[email protected]>
Cc: Dave Hansen <[email protected]>
Cc: Fenghua Yu <[email protected]>
Cc: H. Peter Anvin <[email protected]>
Cc: Linus Torvalds <[email protected]>
Cc: Oleg Nesterov <[email protected]>
Cc: Thomas Gleixner <[email protected]>
Signed-off-by: Ingo Molnar <[email protected]>
---
 arch/x86/kernel/i387.c | 2 --
 1 file changed, 2 deletions(-)

diff --git a/arch/x86/kernel/i387.c b/arch/x86/kernel/i387.c
index 909d10d2fb70..76006a701dbb 100644
--- a/arch/x86/kernel/i387.c
+++ b/arch/x86/kernel/i387.c
@@ -291,8 +291,6 @@ static int fpu__unlazy_stopped(struct task_struct *child)
                return -EINVAL;
 
        if (tsk_used_math(child)) {
-               if (cpu_has_fpu && child == current)
-                       fpu__save(child);
                task_disable_lazy_fpu_restore(child);
                return 0;
        }
-- 
2.1.0

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