This function is only called for stopped child tasks, so the
fpu__save() branch will never get called - remove it.
Reviewed-by: Borislav Petkov <b...@alien8.de>
Cc: Andy Lutomirski <l...@amacapital.net>
Cc: Dave Hansen <dave.han...@linux.intel.com>
Cc: Fenghua Yu <fenghua...@intel.com>
Cc: H. Peter Anvin <h...@zytor.com>
Cc: Linus Torvalds <torva...@linux-foundation.org>
Cc: Oleg Nesterov <o...@redhat.com>
Cc: Thomas Gleixner <t...@linutronix.de>
Signed-off-by: Ingo Molnar <mi...@kernel.org>
---
arch/x86/kernel/i387.c | 2 --
1 file changed, 2 deletions(-)
diff --git a/arch/x86/kernel/i387.c b/arch/x86/kernel/i387.c
index 909d10d2fb70..76006a701dbb 100644
--- a/arch/x86/kernel/i387.c
+++ b/arch/x86/kernel/i387.c
@@ -291,8 +291,6 @@ static int fpu__unlazy_stopped(struct task_struct *child)
return -EINVAL;
if (tsk_used_math(child)) {
- if (cpu_has_fpu && child == current)
- fpu__save(child);
task_disable_lazy_fpu_restore(child);
return 0;
}
--
2.1.0
--
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