Steve,

On 07/15/2015 11:51 AM, Steven Rostedt wrote:
On Wed, 15 Jul 2015 09:20:42 +0900
AKASHI Takahiro <takahiro.aka...@linaro.org> wrote:

On 07/14/2015 10:31 PM, Steven Rostedt wrote:
On Tue, 14 Jul 2015 21:47:10 +0900
Jungseok Lee <jungseokle...@gmail.com> wrote:

Is the below example an unexpected result?
Entry 17 and 18 are ftrace_call and ftrace_ops_no_ops, respectively.

[snip]

Note, function tracing does not disable interrupts. This looks to be
that an interrupt came in while __aloc_skb() was being traced.

Yeah, I think so, too. But if my insight is correct, it's not __alloc_skb()
but one of functions that it calls. As I said in the commit log message
of patch[1/3], the exact traced function will not be listed by

not patch[1/3], but patch[3/3]

save_stack_trace() because we don't create a stack frame at mcount().
I think this is a flaw in the current implementation (on x86).

what do you think, Steve?


mcount (well ftrace_call actually) does indeed create a stack frame for
itself *and* for what called it. At least on x86_64. See mcount_64.S.

With -pg -mfentry, it creates a stack frame. Without -mfentry, mcount
is called after the current function's frame is made so we don't need
to do much.

Thank you for the explanation. But what I don't really understand here
is why we need to add the "current function" to the stack dump list
returned by save_stack_trace():

In check_stack(),
>        /*
>         * Add the passed in ip from the function tracer.
>         * Searching for this on the stack will skip over
>         * most of the overhead from the stack tracer itself.
>         */
>        stack_dump_trace[0] = ip;
>        max_stack_trace.nr_entries++;

I think that "ip" here is the "return address for func" in your
ascii art, and it should be already in the list if a frame is made
by mcount (or func_call).

In fact, stack tracer on arm64 works OK even without the patch[3/3]
if the code quoted above is commented out.
Even on x86, the code is conditional and not activated if the kernel
is compiled without -mfentry before the following commit:
    commit 4df297129f62 ("tracing: Remove most or all of stack tracer stack size 
from stack_max_size")

So what do I misunderstand here?

Thanks,
-Takahiro AKASHI

Here's what the -mfentry version does:

        pushq %rbp
        pushq 8*2(%rsp)  /* this is the parent pointer */
        pushq %rbp
        movq %rsp, %rbp
        pushq 8*3(%rsp)   /* Return address to ftrace_call */
        pushq %rbp
        movq %rsp, %rbp


Thus the stack looks like this:

                                          <---+
        |                              |     |
        +------------------------------+     |
        | return address for func      |     |
        | return address for func_call |     |
        | original %rbp                |     |
        +------------------------------+     |
        | return address for func      |     |
        | ptr to parent frame (%rbp)   | ----+
        +------------------------------| <-----+
        | return address for func_call |       |
         | ptr to next frame (%rbp)     | ------+
        +------------------------------+ <---+
                                              |
                                              |
  Current %rbp points to func_call frame -----+

  The first box isn't used as a frame, but is used by ftrace_call to save
  information to restore everything properly.

Thus, __alloc_skb() is what is currently being traced.


-- Steve

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