On Mon, Sep 28, 2015 at 12:23 PM, Borislav Petkov <[email protected]> wrote:
> On Mon, Sep 28, 2015 at 11:49:18AM +0200, Dmitry Vyukov wrote:
>> Original code did:
>>
>>      if (p->thread.sp < stack || p->thread.sp >= stack+THREAD_SIZE)
>>            return 0;
>>      fp = *(u64 *)(p->thread.sp);
>>
>> p->thread.sp can change concurrently.
>> So we could check that p->thread.sp is within stack bounds, but then
>> dereference another value (which is already outside of bounds).
>
> Right, we do deref it. I realized that after hitting "Send" :\
>
> Which begs another, probably also stupid, question:
>
> What guarantees the task won't disappear after we've checked p?
>
> I.e., after this:
>
>         if (!p || p == current || p->state == TASK_RUNNING)
>                 return 0;


I have not checked, but I would expect that it is caller's
responsibility. There is generally no way to magically resurrect a
pointer to a freed object passed in.
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