Something like this should work:
sizeof () {
ls -l $1 | sed 's/ */ /g' | cut -f5 -d' '
}
if [ `sizeof $1` -lt `sizeof $2` ]; then
echo $1 is smaller than $2
else
echo $1 is the same or bigger than $2
fi
In the above, the sizeof function returns the size extracted from the
results of an ls -l command. I am using cut -f5 with a blank as the
delimiter to get the fifth column which contains the file size. The sed
command is used to remove multiple blanks. Note that there are *two* blanks
as in:
's/<blank><blank>*/<blank>/g'
Of course, I would not use the above code snippet as is. It will bomb if
either $1 or $2 are blank or refer to a file that does not exist. You
should do your normal command line checking, then use a "test -f" check to
ensure that your files exist and are regular files.
I'm a linux newbie, but I know a little bit about scripting. I hope this
helps.
John Baskette
> ----------
> From: Steve Youngs[SMTP:[EMAIL PROTECTED]]
> Sent: Thursday, October 28, 1999 6:18 PM
> To: Linux-Newbie
> Subject: comparing file sizes
>
>
> Okay, I'm trying to get a script to do one of the following:
>
> if [ sizeof(file1) < sizeof(file2)]; then
> cp file2 file3
> fi
>
> or
>
> if [ sizeof(file1) < 1024 ]; then
> cp file2 file3
> fi
>
>
> The above examples are illustrations only. It is designed just to
> give you an idea of what I am trying to do. Anyone got any ideas?
>
> Richard, you're the "script guru" :-), what do you think?
>
> --
> ---Regards, Steve Youngs------------------------------------------
> | On the box it said "Requires Windows 95, Windows NT or better" |
> | So I installed Linux... |
> -----------------Email:-<[EMAIL PROTECTED]>--ICQ:-34307457---
>
