Well ... let's see.
8192 = 13 bits ~= 8000
16384 = 14 bits ~= 16000
32768 = 15 bits ~= 32000
65536 = 16 bits = your Class B address
So there is just enough room to do what you want. One way to do it is
183.90.0.0/17 -->> ~32000 hosts
183.90.128.0/18 -->> ~16000 hosts
183.90.192.0/19 -->> ~ 8000 hosts
183.90.224.0/19 -->> ~ 8000 hosts
This works from an address-range perspective, but I assume you do realize
that most networking technologies (really, every one I know) will bog down
long before you get to 8000 hosts, never mind 320000, unless you use a lot
of switching or bridging (or more layers of routing) to isolate smaller
physical networks.
Is this what you needed to know, or were you intending something different
by your question? If so, what?
At 03:31 PM 3/16/00 +0530, Siva Guru S.R. wrote:
>"Hello" Listers/Gurus,
> Suppose I have a class B IP Address, say 183.90.0.0.
> Now, I want to set up 4 networks with 32000, 16000, 8000 and 8000 hosts
respectively.
>
> Is it possible ? if so, how ?
------------------------------------"Never tell me the odds!"---
Ray Olszewski -- Han Solo
Palo Alto, CA [EMAIL PROTECTED]
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