On Jun 26, 2014, at 10:55 AM, James Bottomley 
<james.bottom...@hansenpartnership.com> wrote:

> On Thu, 2014-06-26 at 16:53 +0200, Bart Van Assche wrote:
>> On 06/11/14 11:09, Sagi Grimberg wrote:
>>> +   return xfer_len + (xfer_len >> ilog2(sector_size)) * 8;
>> 
>> Sorry that I just noticed this now, but why is a shift-right and ilog2()
>> used in the above expression instead of just dividing the transfer
>> length by the sector size ?
> 
> It's a performance thing.  Division is really slow on most CPUs.
> However, we know the divisor is a power of two so we re-express the
> division as a shift, which the processor can do really fast.
> 
> James

I have done this in the past as well, but have you benchmarked it? Compilers 
typically do the right thing in this case (i.e replace division with shift).

Scott--
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