Hi, list, I've never been terribly clear on this, so I'll ask here. Given a network address of, say, 192.168.0.0 and a netmask of /8, thus 192.168.0.0/8, this means that 8 bits of the network address will be used for the host address, which means that any address in the range 192.168.0.1 - 192.168.0.255 will match. Am I correct?
Thanks, Kurt -- "When you are in it up to your ears, keep your mouth shut." _______________________________________________ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc -> http://www.linux-sxs.org/mailman/listinfo/linux-users
