Ugg, forget that. It was too early to think. What I gave was for x.x.x.x/16
Begin forwarded message: Date: Sun, 23 Mar 2003 08:09:23 -0800 From: Vern W Heesch <[EMAIL PROTECTED]> To: [EMAIL PROTECTED] Subject: Re: Network Address/Netmask Notation You are correct that the first 2 octets are for network number, which leaves the last 2 octets for hosts. So the range of useable host addresses are 192.168.0.1 - 192.168.255.254 with a netmask of 255.255.0.0 On Sun, 23 Mar 2003 10:54:54 -0500 "Kurt Wall" <[EMAIL PROTECTED]> wrote: > Hi, list, > > I've never been terribly clear on this, so I'll ask here. Given > a network address of, say, 192.168.0.0 and a netmask of /8, thus > 192.168.0.0/8, this means that 8 bits of the network address will > be used for the host address, which means that any address in the > range 192.168.0.1 - 192.168.0.255 will match. Am I correct? > > Thanks, > > Kurt > -- > "When you are in it up to your ears, keep your mouth shut." > _______________________________________________ > Linux-users mailing list > [EMAIL PROTECTED] > Unsubscribe/Suspend/Etc -> http://www.linux-sxs.org/mailman/listinfo/linux-users > _______________________________________________ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc -> http://www.linux-sxs.org/mailman/listinfo/linux-users
