Joel Hammer wrote:
I understand that bash will do arithmetic in octal if you prefix the
constant with 0. So:
a=05
b=017
c=$((a*b))
echo $c
yields
75
This is the correct answer, but it is in decimals, not octals.
Is there a way to make echo display octal?
Thanks, Joel
More arithmetic?
echo $((8#$c*1)) gives 61
Tom Wekell
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