This seems more work that it should be. I did solve my problem with bc, but, there must be an easy way to get bash to display octal.
Joel On Wed, Sep 24, 2003 at 06:35:18PM -0700, Tom Wekell wrote: > > Joel Hammer wrote: > > I understand that bash will do arithmetic in octal if you prefix the > > constant with 0. So: > > a=05 > > b=017 > > c=$((a*b)) > > echo $c > > yields > > 75 > > This is the correct answer, but it is in decimals, not octals. > > Is there a way to make echo display octal? > > Thanks, > > Joel > > > > More arithmetic? > > echo $((8#$c*1)) gives 61 > _______________________________________________ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc -> http://www.linux-sxs.org/mailman/listinfo/linux-users
