Papp Tamas wrote:
> On Thu, Dec 10, 2009 at 05:23:55PM +0100, Gabor HALASZ wrote:
>> Papp Tamás wrote:
>>> Papp Tamas wrote, On 2009. 12. 10. 17:08:
>>>> On Thu, Dec 10, 2009 at 04:58:45PM +0100, Gabor HALASZ wrote:
>>>>   
>>>>> r...@x232-2:~# cat /etc/hosts.allow
>>>>> sshd:           192.168.0.0/16
>>>>> slapd:          192.168.0.0/16
>>>>> mountd:         192.168.1.0/24
>>>>> mysqld:         192.168.1.0/24 127.0.0.1/8
>>>>> ALL:            192.168.1.0/24 127.0.0.1/8
>>>>>     
>>>> Telnetelni tudsz a portra?
>>>>   
>>> Ja, es 127.0.0. a 127.0.0.1/8 helyett.
>>>
>> A man szerint mindegy:
>>
>> A string that ends with a `.' character. A host address is matched if 
>> its first numeric fields match the given string.  For example, the 
>> pattern `131.155.'  matches  the  address  of  (almost) 
>> every host on the Eindhoven University network (131.155.x.x).
>>
>> An expression of the form `n.n.n.n/mm' is interpreted as a 
>> 'net/masklength' pair, where `mm' is the number of consecutive `1' bits 
>> in the netmask applied to the `n.n.n.n' address.
> 
> OK, akkor viszont 127.0.0.0/8 .
> 

Miert? Miben ter el a 127.0.0.0/8 definicio a 127.0.0.1/8-tol? Vagy a 
127.-tol?

-- 
Gabor HALASZ <[email protected]>

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