I made a mistake. The right code is :
ioremap(0x20000000,0x40000) and ioremap(0x80000000,0x50000)
Grant Likely a écrit :
On Fri, Sep 19, 2008 at 10:58 AM, Josh Boyer <[EMAIL PROTECTED]> wrote:
On Fri, Sep 19, 2008 at 06:45:01PM +0200,
=?ISO-8859-1?Q?S=E9bastien_Chr=E9tien_ wrote:
if I write :
ioremap(0x20000000,0x40000) and ioremap(0x20000000,0x50000)
Will it crash ?
I have no idea. You haven't given us enough information to really answer
that.
But I can say that the second ioremap() call makes the first ioremap()
both redundant and inefficient. You're using exactly the same base
address so the same region is getting mapped twice. Since the second
call uses a bigger region than the first then the kernel will probably
need to allocate another chunk of virtual address space to map it
instead of reusing the first mapping.
g.
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