On Sun, Oct 09, 2011 at 10:00:54AM +0200, Benjamin Herrenschmidt wrote: > On Sun, 2011-10-09 at 09:35 +0200, Eli Cohen wrote: > > On Sun, Oct 09, 2011 at 09:25:18AM +0200, Benjamin Herrenschmidt wrote: > > > On Thu, 2011-10-06 at 15:57 +0200, Eli Cohen wrote: > > > > On Wed, Oct 05, 2011 at 10:15:02AM +0200, Eli Cohen wrote: > > > > > > > > How about this patch - can you give it a try? > > > > > > > > > > > > >From dee60547aa9e35a02835451d9e694cd80dd3072f Mon Sep 17 00:00:00 2001 > > > > From: Eli Cohen <e...@mellanox.co.il> > > > > Date: Thu, 6 Oct 2011 15:50:02 +0200 > > > > Subject: [PATCH] mlx4_en: Fix blue flame on powerpc > > > > > > > > The source buffer used for copying into the blue flame register is > > > > already in > > > > big endian. However, when copying to device on powerpc, the endianess is > > > > swapped so the data reaches th device in little endian which is wrong. > > > > On x86 > > > > based platform no swapping occurs so it reaches the device with the > > > > correct > > > > endianess. Fix this by calling le32_to_cpu() on the buffer. On LE > > > > systems there > > > > is no change; on BE there will be a swap. > > > > > > That looks wrong. > > Not sure I understand: are you saying that on ppc, when you call > > __iowrite64_copy, it will not reach the device swapped? > > Well, first, what do you mean by "swapped" ? :-) But no, it won't for > all intend and purpose, this is a copy routine, copy routines never > swap, neither do fifo accesses for example. When I say swapped, I mean not necessairliy by software. I think that the chipset will swap the the data. The reason I think so is that the CPU arch is big endian, while PCI bus is defined as little endian. That's why I think a swap will occur in ppc and not in x86. > > > The point is that we must always have the buffer ready in big endian > > in memory. In the case of blue flame, we must also copy it to the > > device registers in pci memory space. So if we use the buffer we > > already prepared, we must have another swap. I can think of a nicer > > way to implement this functionality but the question is do you think > > my observation above is wrong and why. > > No. If it's in memory BE then the copy routine will keep it BE. A copy > routine doesn't swap and doesn't affect endianness. > > Additionally, a swapping phase like you proposed doing 32-bit swaps > means that you know for sure that the buffer is made of 32-bit > quantities, is that the case ? Yes
> Even if you had needed that swap, if your > buffer had contained 16-bit or 64-bit quantities, you're toast. > > What is this buffer anyway ? A descriptor or a network packet ? It's a special descriptor that resides both in memory and also written to the device's register. An it contains both data and control informartion. > > If it's a packet, then it's data, endianness has no meaning (or rather > it has for individual fields of the packets but they are already in the > right format and a 32-bit swap will never be right). > > It's almost never right to perform swapping when copying data (or > reading/writing a FIFO). > > Cheers, > Ben. _______________________________________________ Linuxppc-dev mailing list Linuxppc-dev@lists.ozlabs.org https://lists.ozlabs.org/listinfo/linuxppc-dev