Ben Okopnik wrote:
> On Fri, Apr 03, 2009 at 02:53:24PM -0400, Jim wrote:
>   
>> My charge controller has turned up it's toes.  It wasn't a MPPT 
>> controller so I'm now off the fence about buying one.  I have seen the 
>> Morning Star unit discussed here before.  I'm leaning to the Morningstar 
>> SunSaver 15 Amp unit at about $230.  I have two 95 watt panels.
>>
>> I also see that you can connect panels in series up to 75 volts or so 
>> and use this unit to charge a 12V bank. 
>>  
>> Two questions, does anyone have any other controllers they'd suggest I 
>> look at?
>>     
>
> I've got a BlueSky 2512i 25A regulator (should have bought the iX, darn
> it. I missed the fact that only the iX has an auxiliary battery output;
> I thought both of them did.) Other than that little basic bit, I just
> love the thing: it's boosted my SP output significantly. Oh, and I got a
> really good deal on it from a place in California: $189, if I recall
> correctly. I saw one at a boat show a couple of months ago, where they
> wanted $450 for it.
>
>   
>> And by hooking two panels in series I'd double the voltage and keep the 
>> max current lower than a parallel configuration.
>>     
>
> Actually, no - the current limit on those units only relates to output.
> So, whether you convert, for example, (4 panels * 4A)@19v or (4 panels *
> 19v)@4A, the output is still [email protected] (if I recall the nominal output
> voltage correctly.)
>
>   
>> That means less loss 
>> in the wire.  What I don't know is if one of the panels is blocked, will 
>> that hurt the output of the other panel? 
>>     
>
> In series, yes, it would.
>
>
>   
Hm, OK do these controllers have a separate connection for each solar 
panel?  If not I fail to see how multiple panels would add energy to a 
battery.  If I have two voltage sources, one at 20 volts and one at 15 
volts and hook them in parallel, if there isn't a blocking diode some 
current will flow from the 20 V source to the 15 V source.  If there is 
a blocking diode then the 15 V source will furnish no current to the 
circuit effectively making it useless.  Is there something wrong with 
this logic?

Jim.

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