Andre Poenitz <[EMAIL PROTECTED]> writes: | On Tue, Apr 02, 2002 at 11:39:49AM +0200, Lars Gullik Bjønnes wrote: >> Why? $(foo) ${foo} is makefile variables, i fell down on $(foo) for >> consistency... >> >> IMHO $${foo} looks too much like a makefile variable, where as $$foo >> does not. > | Is $$foo_i equal to $${foo}_i or to $${foo_i} ? > | You might know. I don't.
If so... then $$foo should be prefered unless you need to fiddle with the variable name. -- Lgb