Andre Poenitz <[EMAIL PROTECTED]> writes:
| On Tue, Apr 02, 2002 at 11:39:49AM +0200, Lars Gullik Bjønnes wrote:
>> Why? $(foo) ${foo} is makefile variables, i fell down on $(foo) for
>> consistency...
>>
>> IMHO $${foo} looks too much like a makefile variable, where as $$foo
>> does not.
>
| Is $$foo_i equal to $${foo}_i or to $${foo_i} ?
>
| You might know. I don't.
If so... then $$foo should be prefered unless you need to fiddle with
the variable name.
--
Lgb
